ElementTree.find
- ElementTree.find(match, namespaces=None)
Find first matching element by tag name or path. Same as getroot().find(path), which is Element.find() *path* is a string having either an element tag or an XPath, *namespaces* is an optional mapping from namespace prefix to full name. Return the first matching element, or None if no element was found.
© Python Software Foundation. PSF License Version 2 · Official docs ↗
1 Example
>>> from xml.etree.ElementTree import ElementTree >>> tree = ElementTree() >>> tree.parse("index.xhtml") <Element 'html' at 0xb77e6fac> >>> p = tree.find("body/p") # Finds first occurrence of tag p in body >>> p <Element 'p' at 0xb77ec26c> >>> links = list(p.iter("a")) # Returns list of all links >>> links [<Element 'a' at 0xb77ec2ac>, <Element 'a' at 0xb77ec1cc>] >>> for i in links: # Iterates through all found links ... i.attrib["target"] = "blank" ... >>> tree.write("output.xhtml")
from the Python docs