dict.update

builtins

method of dict

dict.update(**kwargs)
dict.update(mapping, /, **kwargs)
dict.update(iterable, /, **kwargs)

D.update([E, ]**F) -> None.  Update D from mapping/iterable E and F.
If E is present and has a .keys() method, then does:  for k in E.keys(): D[k] = E[k]
If E is present and lacks a .keys() method, then does:  for k, v in E: D[k] = v
In either case, this is followed by: for k in F:  D[k] = F[k]

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